NEET · Chemistry · STD 12 - 3. Chemical kinetics
What is the activation energy for a reaction if its rate doubles when the temperature is raised from \(20\,^oC\) to \(35\,^oC\) ........ \(kJ \,mol^{-1}\) \((R = 8.314\, J \,mol^{-1}\, K^{-1})\)
- A \(34.7\)
- B \(15.1\)
- C \(342\)
- D \(269\)
Answer & Solution
Correct Answer
(A) \(34.7\)
Step-by-step Solution
Detailed explanation
\(\log \frac{k_{2}}{k_{1}}=\frac{E_{a}}{2.303 \,R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right)\) \(k_{2}=2 k_{1}, T_{1}=20+273=293\, \mathrm{K}\)
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