NEET · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The standard heat of formation, in \(kcal / mol ^{\text {of }} Ba ^{2+}\) is :
[Given : standard heat of formation of \(SO _4^{2-}\) ion \(( aq )=-216 kcal / mol\),
Standard heat of crystallisation of
\(BaSO _4(s)=-4.5 kcal / mol\), standard heat of formation of \(\left.BaSO _4(s)=-349 kcal / mol \right]\)
- A \(-128.5\)
- B \(-133.0\)
- C \(+133.0\)
- D \(+220.5\)
Answer & Solution
Correct Answer
(A) \(-128.5\)
Step-by-step Solution
Detailed explanation

\(\Delta H _{\text {crys }}\left( BaSO _4\right)=\Delta H _{ f }\left( BaSO _4\right)-\left[\Delta H _{ f }\left( Ba ^{+2}\right)+\Delta H _{ f }\left( SO _4^{-2}\right)\right] \)
\( -4.5=[-349]-\left[\Delta H _{ f }\left( Ba ^{+2}\right)+(-216)\right] \)
\( \Delta H _{ f }\left( Ba ^{+2}\right)=-128.5 kCal mol ^{-1}\)
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