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NEET · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The standard equilibrium constant, Kp at \(298 K\) for the reaction, \(N _{2}( g )+3 H _{2}( g ) \rightleftharpoons 2 NH _{3}( g ) i s 5.8 \times 10^{5} .\) The value of standard equilibrium constant, if the concentration of gases is expressed in terms of mol/L, will be: [Given : \(R :0.08314 \,L\) \(bar\) \(\,K ^{-1} \,mol ^{-1}]\)
- A \(3.51 \times 10^{6}\)
- B \(3.84 \times 10^{7}\)
- C \(3.56 \times 10^{8}\)
- D \(3.99 \times 10^{9}\)
Answer & Solution
Correct Answer
(C) \(3.56 \times 10^{8}\)
Step-by-step Solution
Detailed explanation
\(K _{ P }= K _{ C } \times( RT )^{\Delta n ( g )}\) \(K _{ C }=\frac{ K _{ P }}{( RT )^{-2}}=\frac{5.8 \times 10^{5}}{(0.08314 \times 298)^{-2}}\)
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