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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The solubility of \(AgCl_{(s)}\) with solubility product \(1.6 \times 10^{-10}\) in \(0.1\, M\, NaCl\) solution would be
- A \(1.26 \times 10^{-5} \,M\)
- B \(1.6 \times 10^{-9} \,M\)
- C \(1.6 \times 10^{-11}\, M\)
- D zero.
Answer & Solution
Correct Answer
(B) \(1.6 \times 10^{-9} \,M\)
Step-by-step Solution
Detailed explanation
\(\mathrm{AgCl} \rightleftharpoons \mathrm{Ag}^{+}+\mathrm{Cl}^{-}\) \(\mathrm{Ag}^{+}\) is \(\mathrm{S}\)
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