NEET · Chemistry · STD 12 - 2. Electrochemistry
The pressure of \(H_2\) required to make the potential of \(H_{2}-\) electrode zero in pure water at \(298\, K\) is
- A \(10^{-10} \,atm\)
- B \(10^{-4}\, atm\)
- C \(10^{-14}\, atm\)
- D \(10^{-12} \,atm\)
Answer & Solution
Correct Answer
(C) \(10^{-14}\, atm\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2}(\mathrm{g})\) \(E_{H^{+} / H_{2}}=-\frac{0.0591}{2} \log \frac{P_{M_{2}}}{\left[H^{+}\right]^{2}}\)
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