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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The percentage of pyridine \((C_5H_5N)\) that forms pyridinium ion \((C_5H_5N^+H)\) in a \(0.10\, M\) aqueous pyridine solution (\(K_b\) for \(C_5H_5N = 1.7 \times 10^{-9}\)) is
- A \(0.0060 \%\)
- B \(0.013\%\)
- C \(0.77\%\)
- D \(1.6\%\)
Answer & Solution
Correct Answer
(B) \(0.013\%\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}+\mathrm{H}_{5} \mathrm{O} \longrightarrow \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}^{+} \mathrm{H}+\mathrm{OH}^{-}\) \(\alpha=\sqrt{\frac{K_{b}}{c}}=\sqrt{\frac{1.7 \times 10^{-9}}{0.1}}=\sqrt{1.7 \times 10^{-8}}\)
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