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NEET · Chemistry · STD 12 -8.1. Aldehydes and ketones
The order of stability of the following tautomeric compounds is \(\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)} \rightleftharpoons \) \(\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)} \rightleftharpoons \) \(\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C = CH - C - C{H_3}}
\end{array}}\limits_{(III)} \)
- A \(II > I > III\)
- B \(II > III > I\)
- C \(I > II > III\)
- D \(III > II > I\)
Answer & Solution
Correct Answer
(D) \(III > II > I\)
Step-by-step Solution
Detailed explanation
The enols of \(\beta\) -dicarbonyl compounds are more stable because of conjugation and intramolecular \(H-\) bonding. Thus, the order of stability is \(\underset{\begin{smallmatrix}
(Stabilised\,\,by\,\,conjugation \\
and\,\,H\,-\,bonding )\\ III
\end{smallmatrix}}{\mathop{\begin{matrix}
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
{{H}_{3}}C-C=CH-C-C{{H}_{3}} \\
\end{matrix}}}\,\) \(>\) \(\mathop {\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)}\) \(>\) \(\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)}\)
(Stabilised\,\,by\,\,conjugation \\
and\,\,H\,-\,bonding )\\ III
\end{smallmatrix}}{\mathop{\begin{matrix}
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
{{H}_{3}}C-C=CH-C-C{{H}_{3}} \\
\end{matrix}}}\,\) \(>\) \(\mathop {\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)}\) \(>\) \(\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)}\)
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