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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The molar solublity of \(\mathrm{CaF}_{2} \left(\mathrm{K}_{\mathrm{sp}}=5.3 \times 10^{-11}\right)\) in \(0.1 \mathrm{M}\) solution of NaF will be
- A \(5.3 \times 10^{-11}\; \mathrm{mol} \mathrm{L}^{-1}\)
- B \(5.3 \times 10^{-8}\; \mathrm{mol} \mathrm{L}^{-1}\)
- C \(5.3 \times 10^{-9}\; \mathrm{mol} \mathrm{L}^{-1}\)
- D \(5.3 \times 10^{-10}\; \mathrm{mol} \mathrm{L}^{-1}\)
Answer & Solution
Correct Answer
(C) \(5.3 \times 10^{-9}\; \mathrm{mol} \mathrm{L}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CaF}_{2}(\mathrm{s}) \rightleftharpoons \mathrm{Ca}^{+2}(\mathrm{aq})+2 \mathrm{F}(\mathrm{aq})\) \((a-s)\quad \quad \quad \quad S\quad \quad \quad \quad 2s\)
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