NEET · Chemistry · STD 11 - 1. Some basic concept of chemistry
The highest number of helium atoms is in
- A \(4\) u of helium
- B \(4 \mathrm{~g}\) of helium
- C \(2.271098 \mathrm{~L}\) of helium at \(STP\)
- D \(4 \mathrm{~mol}\) of helium
Answer & Solution
Correct Answer
(D) \(4 \mathrm{~mol}\) of helium
Step-by-step Solution
Detailed explanation
(\(1\)) \(4 u\) of \(\mathrm{He}=\frac{4 u}{4 u}=1 \mathrm{He}\) atom (\(2\)) \(4 \mathrm{~g}\) of Helium \(=\frac{4 \mathrm{~g}}{4 \mathrm{~g}}\) mole \(=1 \mathrm{~mole}=\mathrm{NA}_{\mathrm{Ae}}\) atom
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