NEET · Chemistry · STD 12 -1. Solution and colligative properties
The Henry's law constant \(\left(\mathrm{K}_H\right)\) values of three gases \((A, B, C)\) in water are \(145,2 \times 10^{-5}\) and \(35\) kbar, respectively. The solubility of these gases in water follow the order:
- A \(B>C>A\)
- B \(A>C>B\)
- C \(A > B > C\)
- D \(B > A > C\)
Answer & Solution
Correct Answer
(A) \(B>C>A\)
Step-by-step Solution
Detailed explanation
Sol. Value of Henry's law constant \(\propto \frac{1}{\text { Solubility of gas }}\) Higher the value of \(\mathrm{K}_{\mathrm{H}}\) at a given pressure, lower is the solubility of the gas in the liquid.
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