NEET · Chemistry · STD 12 - 3. Chemical kinetics

The given graph is a representation of kinetics of a reaction. \([Image]\) The \(y\) and \(x\) axes for zero and first order reactions, respectively are

A zero order \((y=\) concentration and \(x=\) time), first order \((y=\) rate constant and \(x=\) concentration)
B zero order ( \(y=\) rate and \(x=\) concentration), first order \(\left(y=t_{1 / 2}\right.\) and \(x=\) concenration)
C zero order ( \(y=\) rate and \(x=\) concentration), first order \(\left(y=\right.\) rate and \(\left.x= t _{1,2}\right)\)
D zero order ( \(y=\) concentration and \(x=\) time), first order \(\left(y=t_{1 / 2}\right.\) and \(x=\) concentration)

Verified Solution

Answer & Solution

Correct Answer

(B) zero order ( \(y=\) rate and \(x=\) concentration), first order \(\left(y=t_{1 / 2}\right.\) and \(x=\) concenration)

Step-by-step Solution

Detailed explanation

\((I)\) curve is suitable for zero order if \(y=\) rate and \(x =\) concentration because in case of zero order reaction rate is constant and does not depend on conc \(^{n}\). \((II)\) curve is suitable for first order if \(y=t_{1 / 2}\) and \(x=\) conc \(^{n}\) because in case of first order \(t_{1 / 2}\) does not depend on conc \(^{ n }\).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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