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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The dissociation constant of a weak acid is \(1 \times 10^{-4}.\) In order to prepare a buffer solution with a \(pH = 5,\) the \([Salt]/[Acid]\) ratio should be
- A \(4 : 5\)
- B \(10 : 1\)
- C \(5 : 4\)
- D \(1 : 10\)
Answer & Solution
Correct Answer
(B) \(10 : 1\)
Step-by-step Solution
Detailed explanation
Dissociation constant of weak acid \(=1 \times 10^{-4}\) the \(\mathrm{pH}\) of weak acid \(=5\)
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