NEET · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
The correct order of increasing metallic character of Na, Be, P, Mg and Si is :
- A \(P < Si < Be < Mg < N a\)
- B \(P < Si < Na < Mg < Be\)
- C \(P < Mg < Be < Si < Na\)
- D \(Be < Si < P < Mg < Na\)
Answer & Solution
Correct Answer
(A) \(P < Si < Be < Mg < N a\)
Step-by-step Solution
Detailed explanation
(A) \(P<S i<B e<M g<N a\)
Metallic character is the tendency of an element to lose electrons. It decreases across a period from left to right and increases down a group.
The elements \(Na , Mg , Si\), and P belong to the third period. Across a period, metallic character decreases, so the order is \(Na > Mg > Si > P\).
The elements Be and Mg belong to Group 2. Down a group, metallic character increases, so \(Mg > Be\).
Comparing Be (a metal) with Si (a metalloid) and P (a non-metal), Be is more metallic than both Si and P .
Combining these observations, the increasing order of metallic character is \(P < Si < Be < Mg < Na\).
Metallic character is the tendency of an element to lose electrons. It decreases across a period from left to right and increases down a group.
The elements \(Na , Mg , Si\), and P belong to the third period. Across a period, metallic character decreases, so the order is \(Na > Mg > Si > P\).
The elements Be and Mg belong to Group 2. Down a group, metallic character increases, so \(Mg > Be\).
Comparing Be (a metal) with Si (a metalloid) and P (a non-metal), Be is more metallic than both Si and P .
Combining these observations, the increasing order of metallic character is \(P < Si < Be < Mg < Na\).
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