NEET · Chemistry · STD 11 - 8.2 Organic chemistry isomerism
The compound which shows metamerism is :
- A \(\mathrm{C}_{5} \mathrm{H}_{12}\)
- B \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\)
- C \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\)
- D \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) This molecular formula is applicable for homologous series ether (-O-) a bivalent functional group and as we know ether with minimum four-C shows metamerism. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\, \&\, \mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\) are metamers.
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