NEET · Chemistry · STD 12 - 6. Haloalkanes and Haloarenes
The compound \(\mathrm{C}_{7} \mathrm{H}_{8}\) undergoes the following reactions: \(\mathrm{C}_{7} \mathrm{H}_{8} \stackrel{3 \mathrm{Cl}_{2} / \Delta}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Br}_{2} / \mathrm{Fe}}{\rightarrow} \mathrm{B} \stackrel{\mathrm{Zn} / \mathrm{HCl}}{\rightarrow} \mathrm{C}\) The product '\(C\)' is
- A \(m-\)bromotoluene
- B \(o-\)bromotoluene
- C \(3 -\)bromo\(-2,4,6-\)-trichlorotuene
- D \(p-\)bromotoluene
Answer & Solution
Correct Answer
(A) \(m-\)bromotoluene
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