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NEET · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

The bond dissociation energies of \(\mathrm{X}_{2}, \mathrm{Y}_{2}\) and \(\mathrm{XY}\) are in the ratio of \(1: 0.5: 1 . \Delta \mathrm{H}\) for the formation of \(\mathrm{XY}\) is \(-200\; \mathrm{kJ} \mathrm{mol}^{-1} .\) The bond dissociation energy of \(X_2\) will be......\(\mathrm{kJ} \mathrm{mol}^{-1}\)

  1. A \(200\)
  2. B \(100\)
  3. C \(800\)
  4. D \(400\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(800\)

Step-by-step Solution

Detailed explanation

let B.E. of \(\mathrm{x}_{2}, \mathrm{y}_{2} \;and\; \mathrm{xy}\) are \(\mathrm{x} \;\mathrm{kJ}\; mol^{-1}\) \(0.5 \;\mathrm{x} \mathrm{kJ} \mathrm{mol}^{-1}\) and \(\mathrm{x}\; \mathrm{kJ} \mathrm{mol}^{-1}\) respectively