The amine that reacts will Hinsberg's reagent to give an alkali insoluble product is

1. A \(\begin{array}{*{20}{c}}
     {C{H_3} - CH - NH - CH - C{H_3}} \\ 
     {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,} \\ 
     {\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
   \end{array}\)
2. B \(\begin{array}{*{20}{c}}
     {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - C{H_3}} \\ 
     | \\ 
     {C{H_3} - C{H_2} - N - C{H_2} - C{H_3}} 
   \end{array}\)
3. C \(\begin{array}{*{20}{c}}
     {N{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
     {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
     {C{H_3} - C - C{H_2} - C{H_2} - C{H_3}} \\ 
     {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
     {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
   \end{array}\)
4. D \(\begin{array}{*{20}{c}}
     {C{H_3}\,\,\,\,\,\,\,\,\,\,} \\ 
     {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
     {C{H_3} - C - CH - N{H_2}} \\ 
     {|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,} \\ 
     {C{H_3}\,\,C{H_3}} 
   \end{array}\)