Predict the correct intermediate and product in the following reaction : \({H_3}C - C \equiv CH\,\xrightarrow[{HgS{O_4}}]{{{H_2}O,\,{H_2}S{O_4}}}\,\mathop {Intermediate}\limits_{(A)} \,\)\( \to \,\mathop {\Pr oduct}\limits_{(B)} \)

1. A \(A \,: \, \begin{array}{*{20}{c}}
     {{H_3}C - C = C{H_2}} \\ 
     | \\ 
     {OH} 
   \end{array}\)     \( B\,\, :\, \begin{array}{*{20}{c}}
     {{H_3}C - C = C{H_2}} \\ 
     | \\ 
     {S{O_4}} 
   \end{array}\)
2. B \(A\,\, :\,\begin{array}{*{20}{c}}
     {{H_3}C - C - C{H_3}} \\ 
     {|\,|} \\ 
     O 
   \end{array}\)    \(B\,\,:\, H_3C-C=CH\)
3. C \(A \,: \, \begin{array}{*{20}{c}}
     {{H_3}C - C = C{H_2}} \\ 
     | \\ 
     {OH} 
   \end{array}\)     \(B\,\, :\,\begin{array}{*{20}{c}}
     {{H_3}C - C - C{H_3}} \\ 
     {|\,|} \\ 
     O 
   \end{array}\)
4. D \( A\,\, :\, \begin{array}{*{20}{c}}
     {{H_3}C - C = C{H_2}} \\ 
     | \\ 
     {S{O_4}} 
   \end{array}\)     \(B\,\, :\,\begin{array}{*{20}{c}}
     {{H_3}C - C - C{H_3}} \\ 
     {|\,|} \\ 
     O 
   \end{array}\)