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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
\(\mathrm{pH}\) of a saturated solution of \(\mathrm{Ca}(\mathrm{OH})_{2}\) ts \(9 .\) The solublity product \(\left(\mathrm{K}_{\mathrm{sp}}\right)\) of \(\mathrm{Ca}(\mathrm{OH})_{2}\) is
- A \(0.5 \times 10^{-15}\)
- B \(0.25 \times 10^{-10}\)
- C \(0.125 \times 10^{-15}\)
- D \(0.5 \times 10^{-10}\)
Answer & Solution
Correct Answer
(A) \(0.5 \times 10^{-15}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s})\rightleftharpoons \mathrm{Ca}^{+2}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})\) \(\mathrm{pH}=9 ; \mathrm{pOH}=5 ; \mathrm{[OH]}^{-}=10^{-5}=2 \mathrm{S}\)
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