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NEET · Chemistry · STD 12 - 7. Alcohol, phenol and ethers

Match List I with List II :
List-IList-II
(A)
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(I) (i) oleum;
(ii) \(H _2 O / H ^{+}\)
(iii) \(H ^{+}\)
(B)
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(II) (i) \(O _2\);
(ii) \(H _2 O / H ^{+}\)
(C)
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(III) (i) \(CH _3 OH , H ^{+}\);
(ii) \(H _2\), catalyst
(D)
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(IV) (i) conc. \(H _2 SO _4, \triangle\);
(ii) \(H ^{+} / H _2 O\)
Choose the correct answer from the options given below:

  1. A A-II, B-III, C-I, D-IV
  2. B A-II, B-III, C-IV, D-I
  3. C A-II, B-IV, C-III, D-I
  4. D A-I, B-III, C-IV, D-II
Verified Solution

Answer & Solution

Correct Answer

(B) A-II, B-III, C-IV, D-I

Step-by-step Solution

Detailed explanation

(B) A-II, B-III, C-IV, D-I
Reaction A: Cumene (isopropylbenzene) is oxidized in the presence of air ( \(O _2\) ) to form cumene hydroperoxide, which upon subsequent treatment with dilute acid \(\left( H _2 O / H ^{+}\right)\)yields phenol and acetone. Thus, A matches II.
Reaction B: Acetic acid \(\left( CH _3 COOH \right)\) can be converted to ethanol by first reacting with methanol in the presence of an acid catalyst to form methyl acetate (esterification). The ester is then catalytically hydrogenated ( \(H _2\), catalyst) to yield ethanol and methanol. Thus, B matches III.
Reaction C: Propan-1-ol is dehydrated using concentrated \(H _2 SO _4\) and heat to form propene. Acid-catalyzed hydration ( \(H ^{+} / H _2 O\) ) of propene follows Markovnikov's rule to yield propan-2-ol. Thus, C matches IV.
Reaction D: Benzene is sulfonated using oleum to form benzenesulfonic acid. Heating with NaOH (fusion) converts it to sodium phenoxide, which on acidification \(\left( H ^{+}\right)\)gives phenol. Thus, D matches I.
The correct matching is A-II, B-III, C-IV, D-I.