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NEET · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

Match List I with List II :
List-IList-II
(A) \(C _2 H _4\)(I) \(3 \sigma\) bonds, \(2 \pi\) bonds
(B) \(C _2 H _2\)(II) \(3 \sigma\) bonds, one lone pair
(C) \(CH _4\)(III) \(4 \sigma\) bonds
(D) \(NH _3\)(IV) \(5 \sigma\) bonds, \(1 \pi\) bond
Choose the correct answer from the options given below:

  1. A A-III, B-IV, C-II, D-I
  2. B A-IV, B-I, C-III, D-II
  3. C A-I, B-II, C-IV, D-III
  4. D A-II, B-III, C-I, D-IV
Verified Solution

Answer & Solution

Correct Answer

(B) A-IV, B-I, C-III, D-II

Step-by-step Solution

Detailed explanation

(B) A-IV, B-I, C-III, D-II
For \(C _2 H _4\) (Ethene), the structure is \(H _2 C = CH _2\). It contains \(4 C - H\) single bonds and \(1 C = C\) double bond. A single bond is a \(\sigma\) bond, and a double bond consists of \(1 \sigma\) and \(1 \pi\) bond. Total bonds: \(5 \sigma\) bonds and \(1 \pi\) bond. Thus, A matches IV.
For \(C _2 H _2\) (Ethyne), the structure is \(HC \equiv CH\). It contains \(2 C - H\) single bonds and \(1 C \equiv C\) triple bond. A triple bond consists of \(1 \sigma\) and \(2 \pi\) bonds. Total bonds: \(3 \sigma\) bonds and \(2 \pi\) bonds. Thus, B matches I.
For \(CH _4\) (Methane), the central carbon atom is bonded to 4 hydrogen atoms via single bonds. Total bonds: \(4 \sigma\) bonds. Thus, C matches III.
For \(NH _3\) (Ammonia), the central nitrogen atom is bonded to 3 hydrogen atoms via single bonds and has 1 lone pair of electrons. Total bonds: \(3 \sigma\) bonds and one lone pair. Thus, D matches II.
The correct matching is A-IV, B-I, C-III, D-II.