NEET · Chemistry · STD 12 - 2. Electrochemistry
Match List \(I\) with List \(II\).
| List \(I\) (Conversion) | List \(II\) (Number of Faraday required) |
| \(A\). \(1 \mathrm{~mol}\) of \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\) | \(l\). \(3 \mathrm{~F}\) |
| \(B\). \(1 \mathrm{~mol}\) of \(\mathrm{MnO}_4^{-}\)to \(\mathrm{Mn}^{2+}\) | \(II\). \(2 F\) |
| \(C\). \(1.5 \mathrm{~mol}\) of \(\mathrm{Ca}\) from molten \(\mathrm{CaCl}_2\) | \(III\). \(1F\) |
| \(D\). \(1 \mathrm{~mol}\) of \(\mathrm{FeO}\) to \(\mathrm{Fe}_2 \mathrm{O}_3\) | \(IV\). \(5 \mathrm{~F}\) |
- A \( A-III, B-IV, C-I, D-II\)
- B \( A-II, B-III, C-I, D-IV\)
- C \(A-III, B-IV, C-II, D-I\)
- D \( A-II, B-IV, C-I, D-III\)
Answer & Solution
Correct Answer
(D) \( A-II, B-IV, C-I, D-III\)
Step-by-step Solution
Detailed explanation
Sol. \(4 \mathrm{OH}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2+4 \mathrm{e}^{-}\) for 2 mole of \(\mathrm{H}_2 \mathrm{O}=4 \mathrm{~F}\) charge is required for 1 mole of \(\mathrm{H}_2 \mathrm{O}=\frac{4 \mathrm{~F}}{2}=2 \mathrm{~F}\) required
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