ExamBro
ExamBro
NEET · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

Match List \(I\) with List \(II\).
List \(I\) (Compound) List \(II\) (Shape/geometry)
\(A\). \(\mathrm{NH}_3\) \(I\). Trigonal Pyramidal
\(B\). \(\mathrm{BrF}_5\) \(II\). Square Planar
\(C\). \(\mathrm{XeF}_4\) \(III\). Octahedral
\(D\). \(\mathrm{SF}_6\) \(IV\). Square Pyramidal
Choose the correct answer from the options given below:

  1. A \( A-II, B-IV, C-III, D-I\)
  2. B \(A-III, B-IV, C-I, D-II\)
  3. C \(A-II, B-III, C-IV, D-I\)
  4. D \(A-I, B-IV, C-II, D-III\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(A-I, B-IV, C-II, D-III\)

Step-by-step Solution

Detailed explanation

\(\mathrm{NH}_3 \Rightarrow s p^3\) hybridised with \(1\) lone pair. Structure will be Trigonal Pyramidal.
Same subject
Explore more questions on app