NEET · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Match List \(I\) with List \(II\).
| List \(I\) (Compound) | List \(II\) (Shape/geometry) |
| \(A\). \(\mathrm{NH}_3\) | \(I\). Trigonal Pyramidal |
| \(B\). \(\mathrm{BrF}_5\) | \(II\). Square Planar |
| \(C\). \(\mathrm{XeF}_4\) | \(III\). Octahedral |
| \(D\). \(\mathrm{SF}_6\) | \(IV\). Square Pyramidal |
- A \( A-II, B-IV, C-III, D-I\)
- B \(A-III, B-IV, C-I, D-II\)
- C \(A-II, B-III, C-IV, D-I\)
- D \(A-I, B-IV, C-II, D-III\)
Answer & Solution
Correct Answer
(D) \(A-I, B-IV, C-II, D-III\)
Step-by-step Solution
Detailed explanation
\(\mathrm{NH}_3 \Rightarrow s p^3\) hybridised with \(1\) lone pair. Structure will be Trigonal Pyramidal.
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