NEET · Chemistry · STD 12 - 5. Co-ordination chemistry
Match List \(I\) with List \(II\).
| List I (Complex) | List \(II\) (Type of isomerism) |
| \(A\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_2\right)\right] \mathrm{Cl}_2\) | \(I\). Solvate isomerism |
| \(B\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}\) | \(II\). Linkage isomerism |
| \(C\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]\) | \(III\). Ionization isomerism |
| \(D\). \(\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3\) | \(IV\). Coordination isomerism |
- A \(A-I, B-III, C-IV, D-II\)
- B \(A-I, B-IV, C-III, D-II\)
- C \(A-II, B-IV, C-III, D-I\)
- D \( A-II, B-III, C-IV, D-I\)
Answer & Solution
Correct Answer
(D) \( A-II, B-III, C-IV, D-I\)
Step-by-step Solution
Detailed explanation
| \(A\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right) 5\left(\mathrm{NO}_2\right)\right] \mathrm{Cl}_2\) | \(II\). Linkage isomerism due to ' \(N\) ' and ' \(\mathrm{O}\) ' linkage by \(\mathrm{NO}_2\) |
| \(B\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}\) | \(III\). Ionization isomerism |
| \(C\). \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]\) | \(IV\). Coordination isomerism |
| \(D\). \(\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3\) | \(I\). Solvate isomerism |
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