NEET · Chemistry · STD 12 - 5. Co-ordination chemistry
Match List I with List II :
| List-I (Complex/ion) | List-II (Shape/geometry) |
| (A) \(\left[ Pt \left( Cl _2\right)\left( NH _3\right)_2\right]\) | (I) Octahedral |
| (B) \(\left[ Co \left( NH _3\right)_6\right] Cl _3\) | (II) Trigonal bipyramidal |
| (C) \(\left[ NiCl _4\right]^2\) | (III) Square planar |
| (D) \(\left[ Fe ( CO )_5\right]\) | (IV) Tetrahedral |
- A A-III, B-IV, C-I, D-II
- B A-III, B-I, C-IV, D-II
- C A-IV, B-I, C-III, D-II
- D A-I, B-III, C-IV, D-II
Answer & Solution
Correct Answer
(B) A-III, B-I, C-IV, D-II
Step-by-step Solution
Detailed explanation
(B) A-III, B-I, C-IV, D-II
For \(\left[ Pt \left( Cl _2\right)\left( NH _3\right)_2\right]\), Pt is in +2 oxidation state. \(Pt ( II )\) complexes are generally square planar with \(d s p^2\) hybridization.
For \(\left[ Co \left( NH _3\right)_6\right] Cl _3\), Co is in +3 oxidation state. With a coordination number of 6 , it forms an octahedral geometry.
For \(\left[ NiCl _4\right]^{2-}, Ni\) is in +2 oxidation state \(\left(3 d^8\right)\). Since \(Cl ^{-}\)is a weak field ligand, no pairing of electrons occurs, resulting in \(s p^3\) hybridization and a tetrahedral geometry.
For \(\left[ Fe ( CO )_5\right]\), Fe is in 0 oxidation state. With a coordination number of 5 , it forms a trigonal bipyramidal geometry with \(d s p^3\) hybridization.
Therefore, the correct matching is \(A \rightarrow III , B \rightarrow I , C \rightarrow IV , D \rightarrow II\).
For \(\left[ Pt \left( Cl _2\right)\left( NH _3\right)_2\right]\), Pt is in +2 oxidation state. \(Pt ( II )\) complexes are generally square planar with \(d s p^2\) hybridization.
For \(\left[ Co \left( NH _3\right)_6\right] Cl _3\), Co is in +3 oxidation state. With a coordination number of 6 , it forms an octahedral geometry.
For \(\left[ NiCl _4\right]^{2-}, Ni\) is in +2 oxidation state \(\left(3 d^8\right)\). Since \(Cl ^{-}\)is a weak field ligand, no pairing of electrons occurs, resulting in \(s p^3\) hybridization and a tetrahedral geometry.
For \(\left[ Fe ( CO )_5\right]\), Fe is in 0 oxidation state. With a coordination number of 5 , it forms a trigonal bipyramidal geometry with \(d s p^3\) hybridization.
Therefore, the correct matching is \(A \rightarrow III , B \rightarrow I , C \rightarrow IV , D \rightarrow II\).
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