ExamBro
ExamBro
NEET · Chemistry · STD 12 - 5. Co-ordination chemistry

Match List I with List II :
List-I (Complex/ion)List-II (Shape/geometry)
(A) \(\left[ Pt \left( Cl _2\right)\left( NH _3\right)_2\right]\)(I) Octahedral
(B) \(\left[ Co \left( NH _3\right)_6\right] Cl _3\)(II) Trigonal bipyramidal
(C) \(\left[ NiCl _4\right]^2\)(III) Square planar
(D) \(\left[ Fe ( CO )_5\right]\)(IV) Tetrahedral
Choose the correct answer from the options given below:

  1. A A-III, B-IV, C-I, D-II
  2. B A-III, B-I, C-IV, D-II
  3. C A-IV, B-I, C-III, D-II
  4. D A-I, B-III, C-IV, D-II
Verified Solution

Answer & Solution

Correct Answer

(B) A-III, B-I, C-IV, D-II

Step-by-step Solution

Detailed explanation

(B) A-III, B-I, C-IV, D-II
For \(\left[ Pt \left( Cl _2\right)\left( NH _3\right)_2\right]\), Pt is in +2 oxidation state. \(Pt ( II )\) complexes are generally square planar with \(d s p^2\) hybridization.
For \(\left[ Co \left( NH _3\right)_6\right] Cl _3\), Co is in +3 oxidation state. With a coordination number of 6 , it forms an octahedral geometry.
For \(\left[ NiCl _4\right]^{2-}, Ni\) is in +2 oxidation state \(\left(3 d^8\right)\). Since \(Cl ^{-}\)is a weak field ligand, no pairing of electrons occurs, resulting in \(s p^3\) hybridization and a tetrahedral geometry.
For \(\left[ Fe ( CO )_5\right]\), Fe is in 0 oxidation state. With a coordination number of 5 , it forms a trigonal bipyramidal geometry with \(d s p^3\) hybridization.
Therefore, the correct matching is \(A \rightarrow III , B \rightarrow I , C \rightarrow IV , D \rightarrow II\).