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NEET · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(KMnO_4\) can be prepared from \(K_2MnO_4\) as per the reaction, \(3MnO_4^{2-} + 2H_2O \rightleftharpoons 2MnO_4^- + MnO_2 + 4OH^-\) The reaction can go to completion by removing \(OH^-\) ions by adding
- A \(CO_2\)
- B \(SO_2\)
- C \(HCl\)
- D \(KOH\)
Answer & Solution
Correct Answer
(A) \(CO_2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{MnO}_{4}^{-}\) oxidizes \(\mathrm{HCl}\) and \(\mathrm{SO}_{2}\) to \(\mathrm{Cl}_{2}\) and \(\mathrm{SO}_{3}\) respectively. \(\mathrm{MnO}_{4}^{-}\) does not oxidizes \(\mathrm{H}_{2} \mathrm{CO}_{3}\) (maximum oxidation state of \(\mathrm{C}\) )
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