NEET · Chemistry · STD 12 - 2. Electrochemistry
In the electrochemical cell : \(Zn \,|\,ZnSO_4\,(0.01\,M)\,||\,CuSO_4\,(1.0\, M)\,|\,Cu,\) the \(emf\) of this Daniell cell is \(E_1.\) When the concentration of \(ZnSO_4\) is changed to \(1.0\, M\) and that of \(CuSO_4\) changed to \(0.01\, M,\) the \(emf\) changes to \(E_2.\) Fromthe followings, which one is the relationship between \(E_1\) and \(E_2\) ? (Given, \(RT/F = 0.059\))
- A \(E_1 < E_2\)
- B \(E_1 > E_2\)
- C \(E_1 = E_2\)
- D none of the above
Answer & Solution
Correct Answer
(B) \(E_1 > E_2\)
Step-by-step Solution
Detailed explanation
For cell \(\mathrm{Zn}\left|\mathrm{ZnSO}_{4}(0.01 \mathrm{M})\right|| \mathrm{CuSO}_{4}(1 \mathrm{M}) | \mathrm{Cu}\)
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