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NEET · Chemistry · STD 12 - 2. Electrochemistry

In the electrochemical cell : \(Zn \,|\,ZnSO_4\,(0.01\,M)\,||\,CuSO_4\,(1.0\, M)\,|\,Cu,\) the \(emf\) of this Daniell cell is \(E_1.\) When the concentration of \(ZnSO_4\) is changed to \(1.0\, M\) and that of \(CuSO_4\) changed to \(0.01\, M,\) the \(emf\) changes to \(E_2.\) Fromthe followings, which one is the relationship between \(E_1\) and \(E_2\) ? (Given, \(RT/F = 0.059\))

  1. A \(E_1 < E_2\)
  2. B \(E_1 > E_2\)
  3. C \(E_1 = E_2\)
  4. D none of the above
Verified Solution

Answer & Solution

Correct Answer

(B) \(E_1 > E_2\)

Step-by-step Solution

Detailed explanation

For cell \(\mathrm{Zn}\left|\mathrm{ZnSO}_{4}(0.01 \mathrm{M})\right||  \mathrm{CuSO}_{4}(1 \mathrm{M}) | \mathrm{Cu}\)