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NEET · Chemistry · STD 11 - 2. structure of atom
In hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is \([\) Given that Bohr radius, \(a_0 = 52.9 \;pm]\)
- A \(211.6 \;pm\)
- B \(211.6\pi \;pm\)
- C \(52.9\pi \;pm\)
- D \(105.8 \;pm\)
Answer & Solution
Correct Answer
(B) \(211.6\pi \;pm\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n} \lambda=2 \pi \mathrm{r}\) \(\mathrm{n} \lambda=2 \pi \frac{\mathrm{n}^{2}}{\mathrm{z}} \mathrm{a}_{0}\)
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