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NEET · Chemistry · STD 12 - 3. Chemical kinetics
If the rate constant for a first order reaction is \(\mathrm{k}\), the time \((t)\) required for the completion of \(99 \%\) of the reaction is given by
- A \(\mathrm{t}=0.693 / \mathrm{k}\)
- B \(\mathrm{t}=6.909 / \mathrm{k}\)
- C \(\mathrm{t}=4.606 / \mathrm{k}\)
- D \(\mathrm{t}=2.303 / \mathrm{k}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{t}=4.606 / \mathrm{k}\)
Step-by-step Solution
Detailed explanation
For first order reaction \(\mathrm{k}=\frac{1}{\mathrm{t}} \ln \left[\frac{\mathrm{A}_{\mathrm{o}}}{\mathrm{A}_{\mathrm{t}}}\right] \quad \begin{array}{ll}{\text { For } 99 \% \text { completion, }} \\ {[\mathrm{A}]_{\mathrm{o}}=100, \quad \mathrm{[A]}_{\mathrm{t}}=1}\end{array}\)
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