NEET · Chemistry · STD 12 - 2. Electrochemistry
If the molar conductivity \(\left(\Lambda_{ m }\right)\) of a \(0.050 mol L ^{-1}\) solution of a monobasic weak acid is \(90 S cm ^2 mol^{-1}\), its extent (degree) of dissociation will be [Assume \(\Lambda_{+}^{\circ}=349.6 S cm ^2 mol^{-1}\) and \(\Lambda_{-}^{\circ}=50.4 S cm ^2 mol^{-1}\).]
- A 0.115
- B 0.125
- C 0.225
- D 0.215
Answer & Solution
Correct Answer
(C) 0.225
Step-by-step Solution
Detailed explanation
Degree of dissociation \((\alpha)=\frac{\Lambda_m}{\Lambda_m^{\circ}}\)
\(\Lambda_{ m }^{\circ}=\Lambda_{+}^{\circ}+\Lambda_{-}^{\circ}\)
\(=349.6+50.4=400 Scm ^2 mol^{-1}\)
\(\therefore \alpha=\frac{\Lambda_{ m }}{\Lambda_{ m }^{\circ}}=\frac{90}{400}=0.225\)
\(\Lambda_{ m }^{\circ}=\Lambda_{+}^{\circ}+\Lambda_{-}^{\circ}\)
\(=349.6+50.4=400 Scm ^2 mol^{-1}\)
\(\therefore \alpha=\frac{\Lambda_{ m }}{\Lambda_{ m }^{\circ}}=\frac{90}{400}=0.225\)
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