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NEET · Chemistry · STD 12 - 2. Electrochemistry

Identify the reaction from following having top position in \(EMF\) series (Std. red. potential) according to their electrode potential at \(298 \;K\).

  1. A \(K ^{+}+1 e ^{-} \rightarrow K _{( s )}\)
  2. B \(Mg ^{2+}+2 e ^{-} \rightarrow Mg _{( s )}\)
  3. C \(Fe ^{2+}+2 e ^{-} \rightarrow Fe _{( s )}\)
  4. D \(Au ^{3+}+3 e ^{-} \rightarrow Au _{( s )}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(Au ^{3+}+3 e ^{-} \rightarrow Au _{( s )}\)

Step-by-step Solution

Detailed explanation

\(A u^{3+}+3 e^{-} \rightarrow A u(s)  E^{0}=1.40 \vee \) \(F e^{2+}+2 e^{-} \rightarrow F e(s)  E^{0}=-0.44 v \)