NEET · Chemistry · STD 12 - p -Block elements - ll
Identify the incorrect statement from the following :
- A Nitrogen can form \(p \pi-p \pi\) multiple bonds with itself.
- B \(P \left( C _2 H _5\right)_3\) and \(As \left( C _6 H _5\right)_3\) form \(d \pi-d \pi\) bond with transition metals.
- C Phosphorus, arsenic and antimony show catenation property.
- D Nitrogen can form \(d \pi-p \pi\) bond with oxygen.
Answer & Solution
Correct Answer
(D) Nitrogen can form \(d \pi-p \pi\) bond with oxygen.
Step-by-step Solution
Detailed explanation
(D) Nitrogen can form \(d \pi-p \pi\) bond with oxygen.
Nitrogen and oxygen both belong to the second period of the periodic table.
The valence shell electronic configuration of nitrogen is \(2 s^2 2 p^3\) and that of oxygen is \(2 s^2 2 p^4\).
Since the principal quantum number is \(n=2\) for both elements, they do not have vacant d-orbitals in their valence shells.
Therefore, nitrogen cannot form \(d \pi-p \pi\) bonds with oxygen. They can only form \(p \pi-p \pi\) multiple bonds.
Statement (1) is correct as nitrogen forms \(p \pi-p \pi\) multiple bonds with itself (e.g., in \(N_2\) ).
Statement (2) is correct because phosphorus and arsenic have vacant d-orbitals and can act as \(\pi\)-acceptor ligands, forming \(d \pi-d \pi\) back-bonds with the filled d-orbitals of transition metals.
Statement (3) is correct as phosphorus, arsenic, and antimony exhibit the property of catenation.
Thus, the incorrect statement is (4).
Nitrogen and oxygen both belong to the second period of the periodic table.
The valence shell electronic configuration of nitrogen is \(2 s^2 2 p^3\) and that of oxygen is \(2 s^2 2 p^4\).
Since the principal quantum number is \(n=2\) for both elements, they do not have vacant d-orbitals in their valence shells.
Therefore, nitrogen cannot form \(d \pi-p \pi\) bonds with oxygen. They can only form \(p \pi-p \pi\) multiple bonds.
Statement (1) is correct as nitrogen forms \(p \pi-p \pi\) multiple bonds with itself (e.g., in \(N_2\) ).
Statement (2) is correct because phosphorus and arsenic have vacant d-orbitals and can act as \(\pi\)-acceptor ligands, forming \(d \pi-d \pi\) back-bonds with the filled d-orbitals of transition metals.
Statement (3) is correct as phosphorus, arsenic, and antimony exhibit the property of catenation.
Thus, the incorrect statement is (4).
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