NEET · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Hydrolysis of sucrose is glven by the following reactlon. Sucrose \(+\) \(H _{2} O \rightleftharpoons\) Glucose \(+\) Fructose If the equilibrium constant \(\left( K _{c}\right)\) is \(2 \times 10^{13}\) at \(300\, K\), the value of \(\Delta_{ r } G^{\Theta}\) at the same temperature will be:
- A \(-8.314 \,J \,mol ^{-1} K ^{-1} \times 300 K \times \ln \left(4 \times 10^{13}\right)\)
- B \(-8.314\, J\, mol ^{-1} K ^{-1} \times 300 K \times \ln \left(2 \times 10^{13}\right)\)
- C \(8.314\, J\, mol ^{-1} K ^{-1} \times 300\, K \times \ln \left(2 \times 10^{13}\right)\)
- D \(8.314\, J\, mol ^{-1} K ^{-1} \times 300 K \times \ln \left(3 \times 10^{13}\right)\)
Answer & Solution
Correct Answer
(B) \(-8.314\, J\, mol ^{-1} K ^{-1} \times 300 K \times \ln \left(2 \times 10^{13}\right)\)
Step-by-step Solution
Detailed explanation
\(K _{ c }=2 \times 10^{13}\) \(T =300 K\)
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