NEET · Chemistry · STD 12 - 4. d and f- block elements

Given below are certain cations. Using inorganic qualitative analysis, arrange them in increasing group number from 0 to \(\mathrm{VI}\). \(A\). \(Al^{3+}\) \(B\). \(Cu^{2+}\) \(C\). \(Ba^{2+}\) \(D\). \(Co^{2+}\) \(E\). \(Mg^{2+}\) Choose the correct answer from the options given below.

A \(B, C, A, D, E\)
B \(E, C, D, B, A\)
C \(E, A, B, C, D\)
D \(B, A, D, C, E\)

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Answer & Solution

Correct Answer

(D) \(B, A, D, C, E\)

Step-by-step Solution

Detailed explanation

Group	Cations
Group \(-II\)	\(\mathrm{Cu}^{2+}\)
Group \(-III\)	\(\mathrm{Al}^{3+}\)
Group \(-IV\)	\(\mathrm{Co}^{2+}\)
Group \(-V\)	\(\mathrm{Ba}^{2+}\)
Group \(-VI\)	\(\mathrm{Mg}^{2+}\)

The correct order of group number of ions is \(\underset{\text { (B) }}{\mathrm{Cu}^{2+}} < \underset{\text { (A) }}{\mathrm{Al}^{3+}} < \underset{\text { (D) }}{\mathrm{Co}^{2+}} < \underset{\text { (C) }}{\mathrm{Ba}^{2+}} < \underset{\text { (E) }}{\mathrm{Mg}^{2+}}\) \(\therefore\) The correct order is \(\mathrm{B}, \mathrm{A}, \mathrm{D}, \mathrm{C}, \mathrm{E}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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