NEET · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For the reaction, \(X_2O_{4(l)} \to 2XO_{2(g)}\) \(\Delta U = 2.1\ kcal, \, \Delta S = 20\, cal\, K^{-1}\) at \(300\, K\) Hence, \(\Delta G\) is ............ \(\mathrm{kcal}\)
- A \(2.7\)
- B \(- 2.7\)
- C \(9.3\)
- D \(- 9.3\)
Answer & Solution
Correct Answer
(B) \(- 2.7\)
Step-by-step Solution
Detailed explanation
\(\Delta H=\Delta U+\Delta n_{g} R T\) Given, \(\Delta U=2.1 \,\mathrm{kcal}, \Delta n_{g}=2\)
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