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NEET · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

For the reaction \(A ( g ) \rightleftharpoons 2 B( g )\), the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500 , at 1000 K .
[Given : \(\text{R} =0.0831 \text{L atm mol} ^{-1} \text{K}^{-1}\)]
\(\text{K} _{\text{p}}\) for the reaction at 1000 K is ________.

  1. A 83.1
  2. B \(2.077 \times 10^5\)
  3. C 0.033
  4. D 0.021
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Answer & Solution

Correct Answer

(C) 0.033

Step-by-step Solution

Detailed explanation

\(\begin{aligned} K _{ C } & =\frac{ K _{ f }}{ K _{ b }} \\ & =\frac{ K _{ f }}{2500 K_{ f }} \\ & =\frac{1}{2500} \\ K_{ p } & = K _{ C }( RT )^{\Delta n _{ g }} \\ = & \frac{1}{2500}(0.0831 \times 1000)^1 \\ K_{ p } & =0.033\end{aligned}\)
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