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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

Following solutions were prepared by mixing different volumes of \(NaOH\) and \(HCl\) of different concentrations \((a)\;\;60\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+40 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}\) \((b)\;\;55\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+45 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}\) \((c)\;\;75\; \mathrm{mL} \frac{\mathrm{M}}{5}\; \mathrm{HCl}+25 \;\mathrm{mL} \frac{\mathrm{M}}{5} \;\mathrm{NaOH}\) \((d)\;\;100\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+100 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}\) \(pH\) of which one of them will be equal to \(1\) ?

  1. A \((b)\)
  2. B \((a)\)
  3. C \((d)\)
  4. D \((c)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((c)\)

Step-by-step Solution

Detailed explanation

As \(\mathrm{N}_{1} \mathrm{V}_{1}>\mathrm{N}_{2} \mathrm{V}_{2}\) So acid is left at the end of reaction
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