NEET · Chemistry · STD 12 - 5. Co-ordination chemistry

Ethylene diaminetetraacetate \((EDTA)\) ion is :

A Hexadentate ligand with four \("O"\) and two \("N"\) donor atoms
B Unidentate ligand
C Bidentate ligand with two \("N''\) donor atoms
D Tridentate ligand with three \("N"\) donor atoms

Verified Solution

Answer & Solution

Correct Answer

(A) Hexadentate ligand with four \("O"\) and two \("N"\) donor atoms

Step-by-step Solution

Detailed explanation

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List\(-l\) with List\(-ll\) :

List\(-I\) (Oxoacids of Sulphur)	List\(-II\) (Bonds)
\(A\). Peroxodisulphuric acid	\(I\). Two \(S - OH\), Four \(S = O\), One \(S - O - S\)
\(B\). Sulphuric acid	\(II\). Two \(S - OH\), One \(S = O\)
\(C\). Pyrosulphuric acid	\(III\). Two \(S - OH\), Four \(S = O\), One \(S - O - O - S\)
\(D\). Sulphurous acid	\(IV\). Two \(S - OH\), Two \(S = O\)

Choose the correct answer from the options given below.

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Hydrolysis of sucrose is glven by the following reactlon. Sucrose \(+\) \(H _{2} O \rightleftharpoons\) Glucose \(+\) Fructose If the equilibrium constant \(\left( K _{c}\right)\) is \(2 \times 10^{13}\) at \(300\, K\), the value of \(\Delta_{ r } G^{\Theta}\) at the same temperature will be:

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