NEET · Chemistry · STD 12 -8.1. Aldehydes and ketones
Consider the reactions, Identify \(A, \,X,\, Y\) and \(Z.\) \(\underset{({{C}_{2}}{{H}_{6}}O)}{\mathop{X}}\,\,\xrightarrow[573\,\,K]{Cu}\) \(A\) \(\xrightarrow[^{-}OH\,,\,\Delta ]{{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}}\) Silver mirror \(A\,\xrightarrow{^{-}OH\,,\,\Delta }Y\) \(A\,\xrightarrow{N{{H}_{2}}NHCON{{H}_{2}}}Z\)
- A \(A-\) Methoxymethane, \(X -\) Ethanol, \(Y-\) Ethanoic acid, \(Z-\) Semicarbazide.
- B \(A-\) Ethanal, \(X -\) Ethanol, \(Y-\) But \(-{2-}\) enal, \(Z-\) Semicarbazone.
- C \(A-\) Ethanol, \(X -\) Acetaldehyde, \(Y-\) Butanone, \(Z-\) Hydrazone.
- D \(A-\) Methoxymethane, \(X -\) Ethanoic acid, \(Y-\) Acetate ion, \(Z-\) Hydrazine.
Answer & Solution
Correct Answer
(B) \(A-\) Ethanal, \(X -\) Ethanol, \(Y-\) But \(-{2-}\) enal, \(Z-\) Semicarbazone.
Step-by-step Solution
Detailed explanation
since '\(A\)' gives positive silver mirror test therefore, it must be an aldehyde or \(\alpha\) -Hydroxyketone. Reaction with semicarbazide indicates that \(A\) can be an aldehyde or ketone.
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