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NEET · Chemistry · STD 12 - 2. Electrochemistry

Consider the half-cell reduction reaction \(Mn^{2+} + 2e^- \rightarrow Mn,\, \)\(E^o = - 1.18\, V\) \(Mn^{2+} \rightarrow  Mn^{3+} + e^-,\) \( E^o = - 1.51 \,V\) The \(E^o\) for the reaction \(3Mn^{2+} \rightarrow  Mn^o + 2Mn^{3+},\) and possibility of the forward reaction are respectively

  1. A \(- 4.18\, V\) and yes
  2. B \(+ 0.33\, V\) and yes
  3. C \(+ 2.69\, V\) and no
  4. D \(- 2.69\, V\) and no
Verified Solution

Answer & Solution

Correct Answer

(D) \(- 2.69\, V\) and no

Step-by-step Solution

Detailed explanation

\(\mathrm{Mn}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Mn}, \mathrm{E}^{\circ}=-1.18 \mathrm{V}\) .... \((i)\) \(2\left(\mathrm{Mn}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Mn}^{2+}\right), E^{\circ}=+1.51 \mathrm{V}\).... \((ii)\)