NEET · Chemistry · STD 11 - 9. Hydricarbon
\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO}^{-} \mathrm{Na}^{+} \xrightarrow[\mathrm{Heat}]{\mathrm{NaOH},+?} \mathrm{CH}_{3} \mathrm{CH}_{3}+ \mathrm{Na}_{2} \mathrm{CO}_{3} .\) Consider the above reaction and identify the missing reagent/chemical.
- A \(\mathrm{B}_{2} \mathrm{H}_{6}\)
- B Red Phosphorus
- C \(\mathrm{CaO}\)
- D \(DIBAL-H\)
Answer & Solution
Correct Answer
(C) \(\mathrm{CaO}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COONa} \xrightarrow[\Delta]{\mathrm{NaOH}+?} \mathrm{CH}_{3}-\mathrm{CH}_{3}\) It's decarboxylation in presence of sodalime so missing reagent is \(\mathrm{CaO} .\) \((\mathrm{NaOH}+\mathrm{CaO})\) sodalime
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