NEET · Chemistry · STD 11 -p-Block elements - I

Boric acid is an acid because its molecule

A contains replaceable \(H^+\) ion
B gives up a proton
C accepts \(OH^-\) from water releasing proton.
D combines with proton from water molecule.

Verified Solution

Answer & Solution

Correct Answer

(C) accepts \(OH^-\) from water releasing proton.

Step-by-step Solution

Detailed explanation

Boric acid is an acid because its molecule accepts \(\mathrm{OH}^{-}\) from water releasing proton \(\mathrm{B}(\mathrm{OH})_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow\left[\mathrm{B}(\mathrm{OH})_{4}\right]^{(-)}(\mathrm{aq})+\mathrm{H}^{(-)}(\mathrm{aq})\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List \(I\) with List \(II\).

List \(I\) (Conversion)	List \(II\) (Number of Faraday required)
\(A\). \(1 \mathrm{~mol}\) of \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\)	\(l\). \(3 \mathrm{~F}\)
\(B\). \(1 \mathrm{~mol}\) of \(\mathrm{MnO}_4^{-}\)to \(\mathrm{Mn}^{2+}\)	\(II\). \(2 F\)
\(C\). \(1.5 \mathrm{~mol}\) of \(\mathrm{Ca}\) from molten \(\mathrm{CaCl}_2\)	\(III\). \(1F\)
\(D\). \(1 \mathrm{~mol}\) of \(\mathrm{FeO}\) to \(\mathrm{Fe}_2 \mathrm{O}_3\)	\(IV\). \(5 \mathrm{~F}\)

Choose the correct answer from the options given below:

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