NEET · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
At a certain temperature,T (K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then, change in internal energy of the system is :
- A 400 J
- B 300 J
- C 700 J
- D 500 J
Answer & Solution
Correct Answer
(B) 300 J
Step-by-step Solution
Detailed explanation
(B) According to the first law of thermodynamics:
\(\Delta U=q+W\)
Heat absorbed by the system, \(q =+500 J\)
Work done by the system, \(W=-200 J\)
Substituting the given values:
\(\Delta U=500+(-200)=300 J\)
\(\Delta U=q+W\)
Heat absorbed by the system, \(q =+500 J\)
Work done by the system, \(W=-200 J\)
Substituting the given values:
\(\Delta U=500+(-200)=300 J\)
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