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NEET · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
At \(100\,^oC\) the \(K_w\) of water is \(55\) times its value at \(25\,^oC.\) What will be the \(pH\) of neutral solution ? \((log\, 55 = 1.74)\)
- A \(7\)
- B \(7.87\)
- C \(5.13\)
- D \(6.13\)
Answer & Solution
Correct Answer
(D) \(6.13\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}^{+}=\sqrt{55 \times 10^{-14}}\) \(\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]\)
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