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NEET · Chemistry · STD 12 - 3. Chemical kinetics
A first order reaction has a rate constant of \(2.303 \times 10^{-3} \;\mathrm{s}^{-1} .\) The time required for \(40 \mathrm{g}\) of this reactant to reduce to \(10\; \mathrm{g}\) will be.....\(s\) [Given that \(\left.\log _{10} 2=0.3010\right]\)
- A \(230.3\)
- B \(301 \)
- C \(2000\)
- D \(602\)
Answer & Solution
Correct Answer
(D) \(602\)
Step-by-step Solution
Detailed explanation
For a first order reaction; \(t_{1 / 2}=\frac{0.693}{\mathrm{K}}\) \(t_{1 / 2}=\frac{0.693}{2.303 \times 10^{-3}}=301 s\)
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