NEET · Chemistry · STD 11 - 2. structure of atom
A bulb is rated at 150 watt, converting \(8 \%\) energy into light. If energy of one photon is \(4.42 \times 10^{-19} J\), how many photons are emitted by the bulb per second?
- A \(2.71 \times 10^{19}\)
- B \(3.06 \times 10^{19}\)
- C \(27.2 \times 10^{19}\)
- D \(1.35 \times 10^{19}\)
Answer & Solution
Correct Answer
(A) \(2.71 \times 10^{19}\)
Step-by-step Solution
Detailed explanation
(A) \(2.71 \times 10^{19}\)
Power of the bulb, \(P=150 W\)
Energy converted into light per second, \(E=8 \%\) of 150 J
\(E=\frac{8}{100} \times 150=12 J\)
Energy of one photon, \(E_p=4.42 \times 10^{-19} J\)
Number of photons emitted per second, \(n=\frac{E}{E_p}\)
\(n=\frac{12}{4.42 \times 10^{-19}}\)
\(n=2.71 \times 10^{19}\)
Power of the bulb, \(P=150 W\)
Energy converted into light per second, \(E=8 \%\) of 150 J
\(E=\frac{8}{100} \times 150=12 J\)
Energy of one photon, \(E_p=4.42 \times 10^{-19} J\)
Number of photons emitted per second, \(n=\frac{E}{E_p}\)
\(n=\frac{12}{4.42 \times 10^{-19}}\)
\(n=2.71 \times 10^{19}\)
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