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NEET · Chemistry · STD 11 - 2. structure of atom
\(4d, 5 \mathrm{p}, 5 \mathrm{f}\) and \(6 \mathrm{p}\) orbitals are arranged in the order of decreasing energy. The correct option is
- A \(5 f>6 p>5 p>4 d\)
- B \(6 p>5 f>5 p>4 d\)
- C \(6 p>5 f>4 d>5 p\)
- D \(5 f>6 p>4 d>5 p\)
Answer & Solution
Correct Answer
(A) \(5 f>6 p>5 p>4 d\)
Step-by-step Solution
Detailed explanation
According to \((n+l)\) rule, correct order of energy is \(5 f>6 \mathrm{p}>5 \mathrm{p}>4 \mathrm{d}\) For same value of \((n+l) ;\) higher is the value of \(n\), higher will be the energy.
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