NEET · Biology · STD 12 - 5. molecular basis of inheritance

Which of the following statement is correct regarding the process of replication in \(E\).coli?

A The \(DNA\) dependent \(RNA\) polymerase catalyses polymerization in one direction, that is \(5^{\prime} \rightarrow 3^{\prime}\)
B The \(DNA\) dependent \(DNA\) polymerase catalyses polymerization in \(5^{\prime} \rightarrow 3^{\prime}\) as well as \(3^{\prime} \rightarrow 5^{\prime}\) direction
C The \(DNA\) dependent \(DNA\) polymerase catalyses polymerization in \(5^{\prime} \rightarrow 3^{\prime}\) direction
D The \(DNA\) dependent \(DNA\) polymerase catalyses polymerization in one direction that is \(3^{\prime} \rightarrow 5^{\prime}\)

Verified Solution

Answer & Solution

Correct Answer

(C) The \(DNA\) dependent \(DNA\) polymerase catalyses polymerization in \(5^{\prime} \rightarrow 3^{\prime}\) direction

Step-by-step Solution

Detailed explanation

In Prokaryotes, like E.coli during replication, the DNA dependent DNA polymerase catalyse polymerization only in one direction, that is \(5^{\prime} \rightarrow 3^{\prime}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the hominids with their correct brain size

\((a)\) Homo habilis	\((i)\) \(900\; \mathrm{cc}\)
\((b)\) Homo neanderthalensis	\((ii)\) \(1350\; \mathrm{cc}\)
\((c)\) Homo erectus	\((iii)\) \(650-800\; \mathrm{cc}\)
\((d)\) Homo sapiens	\((iv)\) \(1400\; \mathrm{cc}\)

Select the correct option. \((a)\quad (b)\quad (c)\quad (d)\)

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