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NEET · Biology · STD 12 - 4. principal of inheritance and variation

The genotypes of a husband and wife are \(I^AI^B\) and \(I^Ai\). Among the blood types of their children, how many different genotypes and phenotypes are possible?

  1. A \(3\) genotypes; \(4\) phenotypes
  2. B \(4\) genotypes; \(3\) phenotypes
  3. C \(4\) genotypes; \(4\) phenotypes
  4. D \(3\) genotypes; \(3\) phenotypes
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\) genotypes; \(3\) phenotypes

Step-by-step Solution

Detailed explanation

(b): If the genotypes of husband and wife are \(I^AI^B\) and \(I^Ai\) respectively, then the probabilities of genotypes and phenotypes among their children can be worked out as:
Genotype: \(I^A I^A\) \( I^Ai\) \( I^AI^B\) \(I^Bi\)
Phenotype: \(A\) \(A\) \(AB\) \(B\)
Thus, there are four possible genotypes, viz., \(I^AI^A, I^Ai, I^AI^B\) and \(I^Bi\) and three possible phenotypes, viz., \(A, AB\) and \(B\) among the children.