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NEET · Biology · STD 12 - 4. principal of inheritance and variation
The genotypes of a husband and wife are \(I^AI^B\) and \(I^Ai\). Among the blood types of their children, how many different genotypes and phenotypes are possible?
- A \(3\) genotypes; \(4\) phenotypes
- B \(4\) genotypes; \(3\) phenotypes
- C \(4\) genotypes; \(4\) phenotypes
- D \(3\) genotypes; \(3\) phenotypes
Answer & Solution
Correct Answer
(B) \(4\) genotypes; \(3\) phenotypes
Step-by-step Solution
Detailed explanation
(b): If the genotypes of husband and wife are \(I^AI^B\) and \(I^Ai\) respectively, then the probabilities of genotypes and phenotypes among their children can be worked out as:
Thus, there are four possible genotypes, viz., \(I^AI^A, I^Ai, I^AI^B\) and \(I^Bi\) and three possible phenotypes, viz., \(A, AB\) and \(B\) among the children.
| Genotype: | \(I^A I^A\) | \( I^Ai\) | \( I^AI^B\) | \(I^Bi\) |
| Phenotype: | \(A\) | \(A\) | \(AB\) | \(B\) |
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