Select the incorrect statement with regard to haemophilia.

(a): Haemophilia is sex­linked disease which is also known as bleeder’s disease as the patient will continue to bleed even from a minor cut since he or she does not possess the natural phenomenon of blood clotting due to absence of antihaemophiliac globulin or factor \(VIII\) (haemophilia -\(A\)) and plasma thromboplastin factor \(IX\) (haemophilia-\(B\), Christmas disease) essential for it. As a result of continuous bleeding the patient may die of blood loss. It is geneticallydue to the presence ofa recessive sex linked gene \(h\), carried by \(X\)-­chromosome. A female becomes haemophiliac only when both of her \(X\)-­chromosomes carry the gene \((X^hX^h)\). However, such females generally die before birth because the combination of these two recessive alleles is lethal. A female having only one allele for haemophilia \((XX^h)\) appears normal because the allele for normal blood clotting present on the other X­chromosome is dominant. Such females are known as carriers. In case of males, a single gene for the defect is able to express itself as the \(Y\)­ chromosome is devoid of any corresponding allele \((X^hY)\).